Deskripsi untuk soal nomor 36 - 37

Perhatikan potongan algoritma berikut.

 for i := 1 to n do begin
 case x of
1: x := (x + 22) mod 6;
2: x := x * 2;
3: dec(x);
4: x := 5 - x;
5: x := x shr 1 + 1;
 else x := (x * 4) mod 5 + 1;
end;
writeln(x);
end;